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## Homework Statement

Find the equation of the tangent to the curve y = x

^{2}(x + 1)

^{4}at the point P(1,16)

## Homework Equations

## The Attempt at a Solution

dy/dx x

^{2}(x + 1)

^{4}

= (x + 1)

^{3}((x + 1)2x + 4x

^{2})

= (x + 1)

^{3}(6x

^{2}+ 2x)

= (x + 1)

^{3}(2x)(3x + 1)

Subst. 1 in to find grad.

(1 + 1)

^{3}(2)(3 + 1)

= 64

Seems wrong..

y - 16 = 64(x - 1)

y = 64x - 48

I think it's probably wrong, just so confused - can someone give me a hand please? Much appreciated